-q^2+3q-4=0

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Solution for -q^2+3q-4=0 equation:


Simplifying
-1q2 + 3q + -4 = 0

Reorder the terms:
-4 + 3q + -1q2 = 0

Solving
-4 + 3q + -1q2 = 0

Solving for variable 'q'.

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
4 + -3q + q2 = 0

Move the constant term to the right:

Add '-4' to each side of the equation.
4 + -3q + -4 + q2 = 0 + -4

Reorder the terms:
4 + -4 + -3q + q2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -3q + q2 = 0 + -4
-3q + q2 = 0 + -4

Combine like terms: 0 + -4 = -4
-3q + q2 = -4

The q term is -3q.  Take half its coefficient (-1.5).
Square it (2.25) and add it to both sides.

Add '2.25' to each side of the equation.
-3q + 2.25 + q2 = -4 + 2.25

Reorder the terms:
2.25 + -3q + q2 = -4 + 2.25

Combine like terms: -4 + 2.25 = -1.75
2.25 + -3q + q2 = -1.75

Factor a perfect square on the left side:
(q + -1.5)(q + -1.5) = -1.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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